X^(2)-36x+299=0

Solution for X^(2)-36x+299=0 equation:

X^(2)-36X+299=0

a = 1; b = -36; c = +299;
Δ = b2-4ac
Δ = -362-4·1·299
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-10}{2*1}=\frac{26}{2}
=13
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+10}{2*1}=\frac{46}{2}
=23
$